Direction (Qs.1 to 5): Study the following information carefully and answer the questions given below.
There are eight children – A, B, C, D, E, F, G and H who live on different floors of a 8 floor building numbered 1 to 8 not necessarily in the same order. They have different chocolates – 11, 16, 19, 25, 34, 41, 46 and 50 again not necessarily in the same order.
The one who lives on 6th floor has 25 chocolates. One child lives between F and the one have 25 chocolates. G lives below F on an even numbered floor. G does not have 25 chocolates. The one having 46 chocolates lives just above G. Two children live between F and H. H lives below F. The total of number of chocolates with D and H is a multiple of 4. Two children live between A and the one having 41 chocolates. A lives above G. The one having 41 chocolates live above A. B has 34 chocolates. The one having 11 chocolates lives just above the one having 16 chocolates. 1 child lives between C and E. The difference between the number of chocolates with E and G is 6.
Question No : 1
How many children live above E?
(1) 1
(2) 2
(3) 4
(4) None
(5) 5
Question No : 2
Who has 41 chocolates?
(1) C
(2) E
(3) F
(4) H
(5) B
Question No : 3
Who lives on third floor?
(1) A
(2) B
(3) C
(4) D
(5) E
Question No : 4
Which of the following is correct with respect to the arrangement?
(1) 2 children live between B and one having 25 chocolates
(2) F lives on floor above A
(3) A lives just below D
(4) H has maximum chocolates
(5) None of these is correct
Question No : 5
What is the sum of chocolates with B and D?
(1) 80
(2) 83
(3) 76
(4) 96
(5) 84